Question 3
A 40 MVA, 20 kV/400 kV, Single phase transformer has the following series impedance
Using the transformer rating as base, determine the per-unit impedance on each side of the transformer (i.e. low/high voltage side).
Provide your response in the comment section using your surname and last two digit of your matriculation number as your identity (e.g. Abacus20)
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Sir are we to just write the final answer.....
ReplyDeleteIn the comment section. Use raw text eg
DeleteVbase= Ibase*Zbase
....
Please show your formula for example if Ibase=20 and Zbase=5, then
DeleteVbase= Ibase*Zbase
Vbase=20*5=100V
Sir the question is not clear.You gave 2 impedance values,is it dat one is the series impedance on the primary,and the other on the secondary?Or we are just to add them up?ciz I added the impedance straight up,since it wasn't specified.Z p.u=12.8+30i(high voltage side). While p.u=0.032+0.072i(on the secondary side).Am I on the righttrack?Or do I still need to make corrections.?I used the formulae; Zbase=(vbase)²/Sbase· and z p.u=Zactual/zbase.(the value of the actual impedances are Z1 and Z2.for both high and low voltage sides).OTUNNI11
ReplyDeleteYou don't need to add them Please separate them.
DeleteZ1 = primary impedance
Z2= secondary impedance
Determine the pu value separately
On the low voltage side(primary side), Zbase=10ohms,While Zp.u=0.1+j0.18.On the high voltage side(secondary),Zbase=4kohms,while p.u=0.032+j0.072.OTUNNI 11
ReplyDeleteWhat is your Vbase and Sbase?
DeleteIn the question, we were asked to use the transformer ratings as our base values.so,my S-base is 40MVA,while my v-bases are 20/400 kV.Am i ryt sir?
ReplyDeleteSorry for the late Reply.
DeleteYes you are correct. I only needed to confirm you know what you're doing.
Good effort!!!
A-base=40MVA while vbase is=20/400KV.Am
ReplyDelete????
DeleteThe A Base is 40MVA
ReplyDeleteThe V Base is 20per400kilovolt
Sir the question is not clear.You gave 2 impedance values,is it dat one is the series impedance on the primary,and the other on the secondary?Or we are just to add them up?ciz I added the impedance straight up,since it wasn't specified.Z p.u=12.8+30i(high voltage side). While p.u=0.032+0.072i(on the secondary side).Am I on the righttrack?Or do I still need to make corrections.?I used the formulae; Zbase=(vbase)²/Sbase· and z p.u=Zactual/zbase.(the value of the actual impedances are Z1 and Z2.for both high and low voltage sides)
ReplyDeleteAbase=40MVA
ReplyDeleteVbase=20/400KV
Sir.
ReplyDeleteThe A Base is 40MVA
The V Base is 20per400kilovolt
Ugele 1059
ReplyDeleteSir the question is not clear.You gave 2 impedance values,is it dat one is the series impedance on the primary,and the other on the secondary?Or we are just to add them up?ciz I added the impedance straight up,since it wasn't specified.Z p.u=12.8+30i(high voltage side). While p.u=0.032+0.072i(on the secondary side).Am I on the righttrack?Or do I still need to make corrections.?I used the formulae; Zbase=(vbase)²/Sbase· and z p.u=Zactual/zbase.(the value of the actual impedances are Z1 and Z2.for both high and low voltage sides)
Ugele 1059
ReplyDeleteSir the question is not clear.You gave 2 impedance values,is it dat one is the series impedance on the primary,and the other on the secondary?Or we are just to add them up?ciz I added the impedance straight up,since it wasn't specified.Z p.u=12.8+30i(high voltage side). While p.u=0.032+0.072i(on the secondary side).Am I on the righttrack?Or do I still need to make corrections.?I used the formulae; Zbase=(vbase)²/Sbase· and z p.u=Zactual/zbase.(the value of the actual impedances are Z1 and Z2.for both high and low voltage sides)